(2x^2+2)(2x^2+x)-6x^2-3x+2=0

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Solution for (2x^2+2)(2x^2+x)-6x^2-3x+2=0 equation:


Simplifying
(2x2 + 2)(2x2 + x) + -6x2 + -3x + 2 = 0

Reorder the terms:
(2 + 2x2)(2x2 + x) + -6x2 + -3x + 2 = 0

Reorder the terms:
(2 + 2x2)(x + 2x2) + -6x2 + -3x + 2 = 0

Multiply (2 + 2x2) * (x + 2x2)
(2(x + 2x2) + 2x2 * (x + 2x2)) + -6x2 + -3x + 2 = 0
((x * 2 + 2x2 * 2) + 2x2 * (x + 2x2)) + -6x2 + -3x + 2 = 0
((2x + 4x2) + 2x2 * (x + 2x2)) + -6x2 + -3x + 2 = 0
(2x + 4x2 + (x * 2x2 + 2x2 * 2x2)) + -6x2 + -3x + 2 = 0
(2x + 4x2 + (2x3 + 4x4)) + -6x2 + -3x + 2 = 0
(2x + 4x2 + 2x3 + 4x4) + -6x2 + -3x + 2 = 0

Reorder the terms:
2 + 2x + -3x + 4x2 + -6x2 + 2x3 + 4x4 = 0

Combine like terms: 2x + -3x = -1x
2 + -1x + 4x2 + -6x2 + 2x3 + 4x4 = 0

Combine like terms: 4x2 + -6x2 = -2x2
2 + -1x + -2x2 + 2x3 + 4x4 = 0

Solving
2 + -1x + -2x2 + 2x3 + 4x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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